Conor McGregor has to lose 27lbs in eight days to make weight for title fight
Conor McGregor must drop just under two stone in just under a week to make his weight for Saturday's interim UFC featherweight title fight with Chad Mendes in Las Vegas.
The Dubliner weighed in at 145lbs exactly when he demolished Denis Siver in Boston earlier this year and must do likewise again this week.
"He's a very big guy. I was impressed with how big he is," Chael Sonnen, a former UFC fighter, told Jim Rome as he spoke about his time with McGregor at ESPN. "I was like 'Conor, what do you weigh?', he said 'I'm around 172 lbs'. He's got to be 145 lbs in eight days."
"He's going to be a little bit bigger than Chad. I don't know if that helps or not. It might slow him down. He's a big guy," he continued. "I've (cut that much weight) before, but I'm considerably bigger. Percentage-wise, I wouldn't have to lose quite as much."
"I don't know how he's going to do it. He's very lean. He has a very busy schedule. He's training at Las Vegas. He was just in LA with Conan O'Brien last night. He's in New York for Reebok a day before that. He was in Connecticut the day before that," he said. "One, how does he do the weight? And two, how does he find the time? I don't know."
McGregor has spoken about making the move to the 155lb weight division in the future.